version 1.326, 2022/07/26 17:33:55
|
version 1.327, 2022/07/27 14:47:35
|
Line 1
|
Line 1
|
/* $Id$ |
/* $Id$ |
$State$ |
$State$ |
$Log$ |
$Log$ |
|
Revision 1.327 2022/07/27 14:47:35 brouard |
|
Summary: Still a problem for one-step probabilities in case of quantitative variables |
|
|
Revision 1.326 2022/07/26 17:33:55 brouard |
Revision 1.326 2022/07/26 17:33:55 brouard |
Summary: some test with nres=1 |
Summary: some test with nres=1 |
|
|
Line 6968 To be simple, these graphs help to under
|
Line 6971 To be simple, these graphs help to under
|
cov[2+nagesqr+Tage[k]]=nbcode[Tvar[Tage[k]]][codtabm(j1,k)]*cov[2]; |
cov[2+nagesqr+Tage[k]]=nbcode[Tvar[Tage[k]]][codtabm(j1,k)]*cov[2]; |
/* cov[++k1]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]*cov[2]; */ |
/* cov[++k1]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]*cov[2]; */ |
} else if(Dummy[Tage[k]]==3){ /* quantitative with age */ |
} else if(Dummy[Tage[k]]==3){ /* quantitative with age */ |
cov[2+nagesqr+Tage[k]]=Tqresult[nres][k]; |
printf("Internal IMaCh error, don't know which value for quantitative covariate with age, Tage[k]%d, k=%d, Tvar[Tage[k]]=V%d, age=%d\n",Tage[k],k ,Tvar[Tage[k]], (int)cov[2]); |
|
exit(1); |
|
/* cov[2+nagesqr+Tage[k]]=meanq[k]/idq[k]*cov[2];/\* Using the mean of quantitative variable Tvar[Tage[k]] /\* Tqresult[nres][k]; *\/ */ |
/* cov[++k1]=Tqresult[nres][k]; */ |
/* cov[++k1]=Tqresult[nres][k]; */ |
} |
} |
/* cov[2+Tage[k]+nagesqr]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]*cov[2]; */ |
/* cov[2+Tage[k]+nagesqr]=nbcode[Tvar[Tage[k]]][codtabm(ij,k)]*cov[2]; */ |